Logan Allen will take the mound in the club’s home opener against the Kansas City Royals on Monday, April 5, making his first career start for Cleveland since being acquired from the San Diego Padres in a three-team mid-season trade in 2019.
Logan Allen will get the start for the Indians' home opener on Monday.— Mandy Bell (@MandyBell02) April 3, 2021
Allen made three appearances out of the bullpen for Cleveland last season, recording a 3.37 ERA through 10.2 innings of work. He had an impressive spring training, outdueling both Triston McKenzie and Cal Quantrill for the fourth spot in the rotation. Allen made four appearances this spring, including two starts, and finished with a 0.64 ERA in 14 innings pitched.
Cleveland’s newest starter boasts a four-pitch arsenal. To go along with his four-seam fastball, Allen utilizes a slider, a changeup, and a curveball. Opposing hitters had a bit too much success against his four-seamer last season, sporting a .421 batting average against it. But he evidently spent the winter retooling his mechanics with the coaching staff at the team’s spring training facility. His newfangled mechanics will make their regular-season debut on Monday.